{"id":34984,"date":"2022-11-21T17:14:58","date_gmt":"2022-11-21T11:44:58","guid":{"rendered":"https:\/\/tsboardsolutions.com\/?p=34984"},"modified":"2022-11-23T16:18:41","modified_gmt":"2022-11-23T10:48:41","slug":"ts-inter-2nd-year-physics-notes-chapter-10","status":"publish","type":"post","link":"https:\/\/tsboardsolutions.com\/ts-inter-2nd-year-physics-notes-chapter-10\/","title":{"rendered":"TS Inter 2nd Year Physics Notes Chapter 10 Alternating Current"},"content":{"rendered":"
Here students can locate TS Inter 2nd Year Physics Notes<\/a> 10th Lesson Alternating Current to prepare for their exam.<\/p>\n \u2192 Alternating Current (AC): If the supplied voltage varies like a sine function then it is called “alternating voltage” and the current driven in the circuit is called “alternating current”.<\/p>\n \u2192 Preference of AC:<\/p>\n \u2192 AC Voltage applied to a Resistor: When a AC Voltage V = Vm<\/sub> sin cot is applied to a pure resistor then current, I = \\(\\frac{V_m}{R}\\) sin \u03c9t = \\(\\frac{\\mathrm{V}}{\\mathrm{R}}\\) and Im<\/sub> = \\(\\frac{V_m}{R}\\) \u2192 Average power consumed in a resistor P = \\(\\frac{1}{2}\\)Im<\/sub>2<\/sup> R(or) P = I2<\/sup>R = VI (\u2235I = Im<\/sub>\/\u221a2)<\/p>\n <\/p>\n \u2192 AC Voltage through an Inductor: in a pure inductor (i.e., where resistance R = 0) applied voltage V = Vm<\/sub> sin \u03c90<\/sub>t. \u2192 AC Voltage through a pure Capacitor: \u2192 Reactance: The resistance of active components like Inductance (L) and Capacitance (C) changes with frequency (co) of current supplied. \u2192 Impedance (Z): The total resistance of a circuit with reactive components like inductance or capacitance or both along with resistance ‘R’ is given by Z = R + XC<\/sub> + XL<\/sub> \u2192 Phasor diagram: Phasor diagram represents the current in a circuit which contains resistance (R) and reactive components like inductance (L) and capacitance ‘C’. \u2192 In a circuit let I is the phasor represents the current it is always parallel to VR i.e., vol\u00actage along resistance. \u2192 Impedance diagram: Graphical represen-tation impedance of Z = \\(\\sqrt{\\mathrm{R}^2+\\left(\\mathrm{X}_{\\mathrm{C}}-\\mathrm{X}_{\\mathrm{L}}\\right)^2}\\) in the form of a right angle triangle is called “impedance diagram”.<\/p>\n \u2192 Impedance diagram <\/p>\n \u2192 Series LCR Circuit: In series LCR circuit an inductance (L), capacitance ‘C’ and resistance ‘R’ are connected to an AC source. AC voltage through LCR ciruit. Let a voltage V = Vm<\/sub> sin cot is applied to series LCR circuit. \u2192 Resonance: Resonance is a physical phenomenon at which a system tends to oscillate freely. This particular frequency is called natural frequency. At resonance amplitude of oscillations is large.<\/p>\n \u2192 Series LCR circuit-Resonant frequency: \u2192 Sharpness of resonance: In case of series LCR circuit resonant frequency \u03c90<\/sub> = \\(\\frac{1}{\\sqrt{\\mathrm{LC}}}\\) \u2192 Power of AC circuit and Power factor: \u2192 Wattless current: In a circuit with pure inductance or pure capacitance the phase angle between voltage and currents are \u03a6 = \\(\\frac{\\pi}{2}\\), so cos \u03a6 = 0. hence no power is dissipated through then even though current passes through them. This current is referred as wattless current.<\/p>\n \u2192 Transformer: A transformer works on the principle of electromagnetic induction”. A transformer will convert high voltage AC current into low voltage AC current or Low voltage AC current into high voltage AC current by keeping VI = constant.<\/p>\n <\/p>\n \u2192 Turns ratio: The ratio of number of turns in primary coil (Np<\/sub>) to number of turns in secondary coil (Ns<\/sub>) is called “transformer turns ratio”. Note:<\/p>\n \u2192 In AC circuits: Voltage at any instant V = Vm<\/sub> sin cot current at any instant I = Im<\/sub> sin cot (where Im<\/sub> = \\(\\frac{V_m}{R}\\))<\/p>\n \u2192 Root mean square values (R.M.S Values): \u2192 Relation between V and I: Vm<\/sub> = Im<\/sub> R and V \u2192 In pure Inductors : V = Vm<\/sub> sin \u03c9t ; I = Im<\/sub> (sin \u03c9t – \u03c0\/2) \u2192 In pure Capacitors : Voltage across capacitor V = \\(\\frac{q}{c}\\) = Vm<\/sub> sin \u03c9t. \u2192 In a resistor: Applied Voltage V = Vm<\/sub> sin \u03c9t \u2192 In series LCR circuit, Resonant frequency \u03c90<\/sub> = \\(\\frac{1}{\\sqrt{\\mathrm{LC}}}\\) <\/p>\n \u2192 In LC CircuIt : Electrical energy stored In charged capacitor UE<\/sub> = \\(\\) where qm<\/sub> = Im<\/sub>\/\u03c90<\/sub> Here students can locate TS Inter 2nd Year Physics Notes 10th Lesson Alternating Current to prepare for their exam. TS Inter 2nd Year Physics Notes 10th Lesson Alternating Current \u2192 Alternating Current (AC): If the supplied voltage varies like a sine function then it is called “alternating voltage” and the current driven in the circuit … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[26],"tags":[],"yoast_head":"\nTS Inter 2nd Year Physics Notes 10th Lesson Alternating Current<\/h2>\n
\n
\nIn a pure resistor applied voltage and current through resistor are in phase, i.e., when voltage is maximum then current is also maximum. Similarly when voltage is minimum the current is also minimum.<\/p>\n
\nCurrent through inductor I = Im<\/sub> sin (\u03c9t – \u03c0\/2) In a pure inductor current lags behind
\nvoltage by a phase angle \u03a6 = \\(\\frac{\\pi}{2}\\)
\nReactance of Inductor XL<\/sub> = \u03c9L<\/sub>
\nIm<\/sub> = \\(\\frac{V_m}{X_L}\\)<\/p>\n
\nWhen AC voltage is applied to a pure capacitor its reactance Xc<\/sub> = \\(\\frac{1}{\\omega \\mathrm{C}}\\). (called capacitive reactance)
\nVoltage across capacitor V = Vm<\/sub> sin \u03c9t
\nCurrent in the capacitor I = Im<\/sub> sin (\u03c9t + \\(\\frac{\\pi}{2}\\)) In a capacitor current (I) leads the applied voltage by an angle \\(\\frac{\\pi}{2}\\).
\nPower dissipation in a pure capacitor Pc<\/sub> = 0<\/p>\n
\nThe resistance that changes with frequency is called reactance (X).
\nReactance of Inductance = XL<\/sub> = \u03c9L
\nReactance of capacitance = XC<\/sub> = \\(\\frac{1}{\\omega \\mathrm{C}}\\)<\/p>\n
\nThe total resistance of a circuit with reactive components is called Impedance.
\nImpedence (Z) of R-L circuit Z = R + \u03c9L
\nImpedance of C – R circuit Z = \\(\\sqrt{R^2+\\left(\\frac{1}{\\omega C}\\right)^2}\\)
\nImpedance of L – C circuit Z = \\(\\sqrt{\\left(\\omega L-\\frac{1}{\\omega \\mathrm{C}}\\right)^2}\\)<\/p>\n
\n<\/p>\n
\nVoltage across capacitor Vc<\/sub> lags behind I by an angle \\(\\frac{\\pi}{2}\\).
\nVoltage across inductor VR leads current phasor I by an angle \\(\\frac{\\pi}{2}\\)
\nPhasor relation is V = VR<\/sub> + VL<\/sub> + Vc<\/sub><\/p>\n
\n
\nWhere
\nX – direction represents Resistance R.
\nY – direction represents total reactance (XC<\/sub> – XL<\/sub>) and Hypotenuse represents impedance.<\/p>\n
\n
\nTotal voltage in the circuit V = VL<\/sub> + VR<\/sub> + VC<\/sub>
\nImpedance of circuit,
\nZ = \\(\\sqrt{R^2+\\left(X_C-X_L\\right)^2}=\\sqrt{R^2+\\left(\\omega L-\\frac{1}{\\omega C}\\right)^2}\\)
\nMaximum current Im<\/sub> = \\(\\frac{\\mathrm{V}_{\\mathrm{m}}}{\\mathrm{Z}}\\)
\nPhase angle \u03a6 = tan\\(\\left(\\frac{\\mathrm{X}_{\\mathrm{C}}-\\mathrm{X}_{\\mathrm{L}}}{\\mathrm{R}}\\right)\\)
\nResonating frequency, \u03c90<\/sub> = \\(\\frac{1}{\\sqrt{\\mathrm{LC}}}\\)<\/p>\n
\nResonant frequency of series LCR circuit is \u03c90<\/sub> = \\(\\frac{1}{\\sqrt{\\mathrm{LC}}}\\)<\/p>\n
\nHowever the amplitude of oscillation is high in between the frequencies \u03c92<\/sub> = \u03c90<\/sub> + \u0394\u03c9 and \u03c91<\/sub> = \u03c90<\/sub> – \u0394\u03c9. Where \u0394\u03c9 is a small frequency change from \u03c90<\/sub>?
\n\u03c92<\/sub> – \u03c91<\/sub> = 2\u0394\u03c9 is called band width of resonance, \u03c90<\/sub>\/2\u0394\u03c9 is called sharpness of resonance.
\nNote: Tuning circuits with sharp resonance are considered as very good frequency selectors.<\/p>\n
\nPower of AC circuit P = I2<\/sup>Z cos\u03a6. It indicates that power depends not only on current I and Impedance Z of circuit but also cosine of phase angle between I and Z.
\nThe term cos \u03a6 is called power factor.<\/p>\n
\nVoltage at secondary, Vs<\/sub> = \\(\\)Vp<\/sub> and
\nCurrent at secondary, Is<\/sub> = \\(\\)Ip<\/sub><\/p>\n\n
\n
\nR.M.S. value of current I = Im<\/sub> \/ \u221a2 = 0.707 Im<\/sub>
\nR.M.S. value of voltage V = Vm<\/sub> \/\u221a2 = 0.707 Vm<\/sub>
\nAverage power
\nP\u0305 = \\(\\frac{1}{2}\\)Im<\/sub>2<\/sup>R = \\(\\frac{1}{2}\\)Iv2<\/sup>\/R = \\(\\frac{1}{2}\\)Im<\/sub>Vm<\/sub><\/p>\n
\n= I R and P = VI = I2<\/sup>R = \\(\\frac{\\mathrm{V}^2}{\\mathrm{R}}\\).<\/p>\n
\nIn inductance current lags behind voltage by 90\u00b0 or \\(\\frac{\\pi}{2}\\) radians.
\nInductive reactance XL<\/sub> = \u03c9L = 2\u03c0\u03c5L
\nMaximum current through inductor Im<\/sub> = \\(\\frac{\\mathrm{V}_{\\mathrm{m}}}{\\mathrm{X}_{\\mathrm{L}}}\\)<\/p>\n
\nCurrent in capacitor I = Im<\/sub> sin (\u03c9t + \u03c0\/2).
\nIn a pure capacitor current I leads voltage V by a phase angle 90\u00b0 or \\(\\frac{\\pi}{2}\\) radians.
\nReactance of capacitor Xc<\/sub> = \\(\\frac{1}{\\omega \\mathrm{C}}\\); Maximum current Im<\/sub> = \\(\\frac{V_m}{(1 \/ \\omega c)}=\\frac{V_m}{X_c}\\)
\nInstantaneous power supplied Pc<\/sub> = \\(\\frac{\\mathrm{i}_{\\mathrm{m}} \\cdot \\mathrm{V}_{\\mathrm{m}}}{2}\\) sin 2\u03c9t.
\nPower supplied to capacitor over one complete cycle is zero.<\/p>\n
\nCurrent I = \\(\\frac{I_m}{R}=\\frac{V_m}{R}\\) sin \u03c9t
\nAverage power dissipated
\nP\u0305 = \\(\\frac{1}{2}\\)I2mR = \\(\\frac{V^2}{R}\\) = VI = \\(\\frac{\\mathrm{V}_{\\mathrm{m}} \\mathrm{I}_{\\mathrm{m}}}{2}\\).<\/p>\n
\nTotal potential in circuit V = VL<\/sub> + VR<\/sub> + Vc<\/sub>.
\n= Vm<\/sub>\/\\(\\frac{V_m}{Z}\\)
\nImpedance of circuit Z = \\(\\sqrt{\\mathrm{R}^2+\\left(\\mathrm{X}_{\\mathrm{C}}-\\mathrm{X}_{\\mathrm{L}}\\right)^2}\\)
\nPhase difference \u03a6 = tan-1<\/sup>\\(\\left[\\frac{\\mathrm{X}_{\\mathrm{C}}-\\mathrm{X}_{\\mathrm{L}}}{\\mathrm{R}}\\right]\\)<\/p>\n
\nAt Resonance \u03c9L = \\(\\frac{1}{\\omega \\mathrm{C}}\\) and Impedance Z = R.
\nBand width of circuit 2\u0394\u03c9 = \u03c92<\/sub> – \u03c91<\/sub>
\n(where \u03c92<\/sub> > \u03c91<\/sub>)
\nSharpness of circuit Q = \\(\\frac{\\omega_0}{2 \\Delta \\omega}=\\frac{\\omega_0 L}{R}\\)
\nPower in AC circuit P = I2<\/sup>Zcos \u03a6 = VIcos \u03a6
\nwhere is phase between voltage V and current I.<\/p>\n
\nResonant frequency \u03c90<\/sub> = \\(\\frac{1}{\\sqrt{\\mathrm{LC}}}\\)
\nIn transformer;
\nTurns ratio = \\(\\frac{\\mathrm{N}_{\\mathrm{s}}}{\\mathrm{N}_{\\mathrm{p}}}\\)
\nSecondary voltage Vs<\/sub> = \\(\\left[\\frac{\\mathrm{N}_{\\mathrm{s}}}{\\mathrm{N}_{\\mathrm{p}}}\\right]\\)Vp<\/sub>
\nSecondary current Is<\/sub> = \\(\\left[\\frac{\\mathrm{N}_{\\mathrm{p}}}{\\mathrm{N}_{\\mathrm{s}}}\\right]\\)Ip<\/sub>
\nBack emf in primary Vp<\/sub> = -Np<\/sub> \\(\\frac{\\mathrm{d} \\phi}{\\mathrm{dt}}\\)
\nInduced emf or voltage in secondary Vs<\/sub> = Ns<\/sub> \\(\\frac{\\mathrm{d} \\phi}{\\mathrm{dt}}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"