{"id":34913,"date":"2022-11-21T12:43:28","date_gmt":"2022-11-21T07:13:28","guid":{"rendered":"https:\/\/tsboardsolutions.com\/?p=34913"},"modified":"2022-11-23T16:18:52","modified_gmt":"2022-11-23T10:48:52","slug":"ts-inter-2nd-year-physics-notes-chapter-13","status":"publish","type":"post","link":"https:\/\/tsboardsolutions.com\/ts-inter-2nd-year-physics-notes-chapter-13\/","title":{"rendered":"TS Inter 2nd Year Physics Notes Chapter 13 Atoms"},"content":{"rendered":"
Here students can locate TS Inter 2nd Year Physics Notes<\/a> 13th Lesson Atoms to prepare for their exam.<\/p>\n \u2192 J.J. Thomson thought that the positive charge of the atom is uniformly distributed through out the volume of the atom and the negatively charged electrons are embedded in it like seeds in a watermelon.<\/p>\n \u2192 According to Rutherford the entire positive charge and most of the mass of the atom is concentrated in a small volume called nucleus. Electrons are revolving around the nucleus at some distance just as planets revolve around the sun.<\/p>\n \u2192 Alpha particle scattering experiments on gold foil showed that size of nucleus is about 10-14<\/sup> to 10-15<\/sup> m and size of atom is nearly 10-10<\/sup> m.<\/p>\n \u2192 Most of the atom is empty space. The electrons would be moving in certain orbits with some distance from nucleus just like planets around the sun.<\/p>\n \u2192 Alpha particle scattering experiment : <\/p>\n \u2192 Impact Parameter: It is the perpendicular distance of the initial velocity vector of a particle from centre of nucleus. \u2192 Bohr postulates : Bohr model of hydrogen atom consists of three main postulates.<\/p>\n \u2192 Bohr radius (a0<\/sub>): According to Bohr theory radius of the orbit, r = \\(\\frac{\\mathrm{n}^2 \\mathrm{~h}^2 \\epsilon_0}{\\pi \\mathrm{me}^2}\\) when n = 1. It is called first orbit. Radius of 1st orbit r1<\/sub> = \\(\\frac{h^2 \\epsilon_0}{\\pi \\mathrm{me}^2}\\) = 5.29 \u00d7 10-11<\/sup> m. This is called Bohr orbit a0<\/sub>. \u2192 Energy of orbit: From Bohr theory energy of the orbit E = –\\(\\frac{m e^4}{8 n^2 h^2 \\epsilon_o^2}\\) \u2192 Spectral series: From Bohr model electrons are permitted to transit between the energy levels while doing so they will absorb or release the exact amount of energy difference of the initial and final states. \u2192 Lyman series: When electrons are jumping on to the first orbit from higher energy levels then that series of spectral lines emitted are called \u201dlyman series”. \u2192 Balmer series : When electrons are jumping on to the second orbit from higher levels then that series of spectral lines are called “Balmer series”. \u2192 Paschen series : When electrons are jump\u00acing on to the 3rd orbit from higher energy levels then that series of spectral lines are called “Paschen series”. \u2192 Brackett series: When electrons are jump\u00acing on to the 4th orbit from higher levels then that series of spectral lines are called “Brackett series”. <\/p>\n \u2192 Pfund series: When electrons are jumping on to the 5th orbit from higher energy levels then that series of spectral lines are called Note : In spectral lines \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{\\mathrm{n}_{\\mathrm{i}}^2}-\\frac{1}{\\mathrm{n}_{\\mathrm{f}}^2}\\right]\\)R Frequency of spectral line v = Rc\\(\\left[\\frac{1}{n_i^2}-\\frac{1}{n_f^2}\\right]\\)<\/p>\n \u2192 Ionisation potential : It is the amount of minimum energy required to release an ele-ctron from the outer most orbit of the nucleus. \u2192 Force between ‘a’ particle and positively charged nucleus \u2192 Kinetic energy of \u03b1 – particle, \u2192 Distance of closest approach d = \\(\\frac{\\mathrm{Ze}^2}{2 \\pi \\varepsilon_0 \\mathrm{k}}\\)<\/p>\n \u2192 For an electron moving in the orbit of hydrogen atom = \\(\\frac{m v^2}{r}=\\frac{1}{4 \\pi \\varepsilon_o} \\frac{Z^2}{r^2}\\)<\/p>\n \u2192 For an atom of atomic number \u2018Z\u2019, \\(\\frac{\\mathrm{mv}^2}{\\mathrm{r}}=\\frac{1}{4 \\pi \\varepsilon_{\\mathrm{o}}} \\frac{\\mathrm{Ze}^2}{\\mathrm{r}^2}\\)<\/p>\n \u2192 Relation between orbit radius and velocity in hydrogen atom is r = e2<\/sup> \/ 4\u03c0\u03b50<\/sub> \u2192 In hydrogen atom . (ii) Potential energy U = \\(\\frac{\\mathrm{e}^2}{8 \\pi \\varepsilon_o \\mathrm{r}}=\\frac{m \\mathrm{e}^4}{8 \\mathrm{n}^2 \\mathrm{~h}^2 \\varepsilon_o^2}\\) (iii) Total energy E = K + U (iv) Velocity of electron in orbit v = e\/\\(\\sqrt{4 \\pi \\varepsilon_o \\mathrm{mr}}\\)<\/p>\n <\/p>\n \u2192 Spectral series: Wavelengths of spectral series are given by \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left(\\frac{1}{\\mathrm{n}_1^2}-\\frac{1}{\\mathrm{n}_2^2}\\right)\\) Velocity of electron in nth orbit Energy of nth orbit Here students can locate TS Inter 2nd Year Physics Notes 13th Lesson Atoms to prepare for their exam. TS Inter 2nd Year Physics Notes 13th Lesson Atoms \u2192 J.J. Thomson thought that the positive charge of the atom is uniformly distributed through out the volume of the atom and the negatively charged electrons are embedded … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":[],"categories":[26],"tags":[],"yoast_head":"\nTS Inter 2nd Year Physics Notes 13th Lesson Atoms<\/h2>\n
\nMagnitude of force between \u03b1 – particle and gold nuclie is F = \\(\\frac{1}{4 \\pi \\epsilon_o} \\frac{(2 \\mathrm{e})(\\mathrm{Ze})}{\\mathrm{r}^2}\\) Where ‘r’ is the distance between \u03b1 – particle and nucleus.
\nThe magnitude and direction of force changes continuously as it approaches the nucleus.<\/p>\n
\nIn case of head on collision impact parameter is minimum and \u03b1 – particle rebounds back (\u03b8 = \u03c0). For a large impact parameter \u03b1 – particle goes undeviated. The chance of head on collision is very small. It in turn suggested that mass of atom is much concentrated in a small volume.<\/p>\n\n
\ni. e., L = nh \/ 2\u03c0 where n = 1, 2, 3, ……………… etc. (an integer.)
\nThese stable orbits are also called as non – radiating orbits.<\/li>\n
\nE = hv = Ei<\/sub>– Ej<\/sub><\/li>\n<\/ul>\n
\na0<\/sub> = \\(\\frac{h^2 \\epsilon_0}{\\pi \\mathrm{me}^2}\\) = 5.29 \u00d7 10-11<\/sup> m = 0.529 \u00c5<\/p>\n
\nWhere – ve sign indicates the force of attraction between electron and nucleus.
\nFor 1st orbit n = 1.
\nIts energy E1<\/sub> = -2.18 \u00d7 10-18<\/sup> J or
\nE1<\/sub> = – 13.6 eV.
\nFor all other orbits their energy E = \\(\\frac{13.6}{n^2}\\) eV
\nNote: The energy of an atom is least (i.e., it has maximum – ve value) when electron is revolving with n = 1 orbit. This energy state (n = 1) is called lowest state of the atom or ground state. For ground state of hydrogen atom E = – 13.6 eV.<\/p>\n
\n\u2234 Energy absorbed or released E = hv = Ei<\/sub> – Ef<\/sub>
\nE = hv = \\(\\frac{\\mathrm{hc}}{\\lambda}=\\frac{m \\mathrm{e}^4}{8 \\varepsilon_{\\mathrm{o}} \\mathrm{h}^2}\\left[\\frac{1}{\\mathrm{n}_{\\mathrm{i}}^2}-\\frac{1}{\\mathrm{n}_{\\mathrm{f}}^2}\\right]\\) or
\n\\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{\\mathrm{n}_{\\mathrm{i}}^2}-\\frac{1}{\\mathrm{n}_{\\mathrm{f}}^2}\\right]\\) where R is Rydberg’s constant R = 1.03 \u00d7 107<\/sup> \/ m<\/p>\n
\nIn Lyman series \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{1^2}-\\frac{1}{n^2}\\right]\\) where n = 2, 3, …… etc<\/p>\n
\nFor Balmer series \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{2^2}-\\frac{1}{\\mathrm{n}^2}\\right]\\) where n = 3,4,………. Spectral lines of Balmer series are in visible region.<\/p>\n
\nFor Paschen series \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{3^2}-\\frac{1}{\\mathrm{n}^2}\\right]\\)
\nn = 4, 5………….. These spectral lines are in near infrared region.<\/p>\n
\nFor Brackett series \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{4^2}-\\frac{1}{n^2}\\right]\\) where n = 5, 6, …………….
\nBrackett series are in middle infrared region.<\/p>\n
\n“pfund series”.
\nFor pfund series \\(\\frac{1}{\\lambda}=\\mathrm{R}\\left[\\frac{1}{5^2}-\\frac{1}{\\mathrm{n}^2}\\right]\\)
\nwhere n = 6, 7, ………… These spectral lines are in far infrared region.<\/p>\n
\nBut \\(\\frac{1}{\\lambda}\\) = v\/c<\/p>\n
\nFrom Bohr’s model energy of the orbit is the ionisation energy of electron in that orbit.
\nEx: Energy of 1st orbit in hydrogen is 13.6 eV.
\nPractically ionisation potential of hydro-gen is 13.6 eV.
\nNote : The success of Bohr atom model is in the prediction of ionisation energy of orbits.<\/p>\n
\nF = \\(\\frac{1}{4 \\pi \\varepsilon_o} \\frac{2 \\mathrm{e}(\\mathrm{Ze})}{\\mathrm{r} 2}=\\frac{\\mathrm{Ze}^2}{2 \\pi \\varepsilon_0 r^2}\\)<\/p>\n
\nK = \\(\\frac{2 Z \\mathrm{e}^2}{4 \\pi \\varepsilon_{\\mathrm{o}} \\mathrm{d}}=\\frac{Z \\mathrm{e}^2}{2 \\pi \\varepsilon_{\\mathrm{o}} \\mathrm{d}}\\)<\/p>\n
\nmv2<\/sup> = \\(\\frac{1}{4 \\pi \\varepsilon_o}\\) where k = \\(\\frac{1}{4 \\pi \\varepsilon_o}\\) = 9 \u00d7 109<\/sup><\/p>\n
\n(1) Kinetic energy K = \\(\\frac{1}{2}\\)mv2<\/sup><\/p>\n
\n= \\(-\\frac{e^2}{4 \\pi \\varepsilon_o r}\\) (-ve sigh for force of attraction)<\/p>\n
\n= \\(-\\frac{e^2}{8 \\pi \\varepsilon_o r}=\\frac{-m e^4}{8 n^2 h^2 \\varepsilon_o^2}\\)<\/p>\n
\nwhere n1<\/sub> and n2<\/sub> are the number of orbits between which electron transition takes place.
\nEnergy radiated In transition E = hv = E2<\/sub> – E1<\/sub>
\nIn Bohr atom model.
\nAngular momentum of orbital L = mvr = \\(\\frac{\\mathrm{nh}}{2 \\pi}\\)
\nradius of nth orbit rn<\/sub> = \\(\\frac{\\mathrm{nh}}{2 \\pi}\\)<\/p>\n
\nVn<\/sub> = e\/\\(\\sqrt{4 \\pi \\varepsilon_o m r_n}\\)
\nor vn<\/sub> = \\(\\frac{1}{\\mathrm{n}} \\frac{\\mathrm{e}^2}{4 \\pi \\varepsilon_{\\mathrm{o}}} \\frac{1}{(\\mathrm{~h} \/ 2 \\pi)}\\)
\nor
\nrn<\/sub> = \\(\\frac{\\mathrm{n}^2 \\mathrm{~h}^2 \\varepsilon_0}{\\pi \\mathrm{me}^4}\\)
\nBohr radius a0<\/sub> = \\(\\frac{h^2 \\varepsilon_o}{\\pi m e^4}\\) = 5.29 \u00d7 10-11<\/sup> m<\/p>\n
\nEn<\/sub> = \\(\\frac{-\\mathrm{me}^4}{8 \\mathrm{n}^2 \\mathrm{~h}^2 \\varepsilon_{\\mathrm{o}}^2}=\\frac{-2.18 \\times 10^{-18}}{\\mathrm{n}^2}\\)J = \\(\\frac{-13.6}{n^2}\\)eV
\nRydberg’s constant R = \\(\\frac{m \\mathrm{e}^4}{8 \\varepsilon_o^2 h^3 \\mathrm{c}}\\)
\n= 1.03 \u00d7 107<\/sup> m-1<\/sup><\/p>\n","protected":false},"excerpt":{"rendered":"